000 00458nam a2200157 4500
001 6493
005 20130515014816.0
008 111112s9999 xx 000 0 und d
050 _aZ6651.P4 1963
100 1 _a"pemberton, john e. "
_917106
245 1 0 _ahow to find out in mathematics:
_b/
_c john.e. pemberton
250 _a1 ed.
260 _auk :
_bpergamon press
_c1963.
300 _a"x, 157p.;
_c20 cm."
942 _2lcc
_cBK
_hZ6651.P4 1963
999 _c27983
_d27983